שינויים

<math>\int\frac{\ln(x)-1}{\ln(x)^2}dx=\int\frac{\ln(x)}{\ln(x)^2}dx-\int\frac{dx}{\ln(x)^2}dx=\int\frac{dx}{\ln(x)}-\int\frac{dx}{\ln(x)^2}</math>