שינויים

/* פתרון */
1.
סמן נסמן
<math>v_{1}=\left(\begin{array}{c}
1\\
\end{array}\right)</math>
מתקיים
<math>Te_{1,1} = T(\left(\begin{array}{ccc}
1 & 0 & 0\\
0 & 0 & 0
1\\
0
\end{array}\right)=1\cdot v_{1}+0\cdot v_{2} \\
Te_{1,2} = \left(\begin{array}{c}
0\\
0
\end{array}\right)=0v_{1}+0v_{2}
Te_{1,3} = \left(\begin{array}{c}
1\\
0
\end{array}\right)=1\cdot v_{1}+0\cdot v_{2}
 
\\
Te_{2,1} = \left(\begin{array}{c}
0\\
1
\end{array}\right)=-1\cdot v_{1}+1\cdot v_{2}
Te_{2,2} = \left(\begin{array}{c}
0\\
0
\end{array}\right)=0v_{1}+0v_{2}
Te_{2,3} = \left(\begin{array}{c}
0\\
1
\end{array}\right)=-1\cdot v_{1}+1\cdot v_{2}</math>
ולכן <math>[T]_{B}^{S}=\left(\begin{array}{cccccc}
1 & 0 & 1 & -1 & 0 & -1\\
0 & 0 & 0 & 1 & 0 & 1
\end{array}\right)</math>
===תרגיל. (6.14)===
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